8y^2+y-7=0

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Solution for 8y^2+y-7=0 equation: 



8y^2+y-7=0

a = 8; b = 1; c = -7;
Δ = b2-4ac
Δ = 12-4·8·(-7)
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$


$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-15}{2*8}=\frac{-16}{16}
=-1
$


$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+15}{2*8}=\frac{14}{16}
=7/8
$

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